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sin3x + sin(7x - ¦Ð) = sin2x
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-2sin2xcos5x = sin2x
´˷½³ÌÓжþ½⣺sin2x = 0, x ÊÇ ¦Ð/2µÄÕû±¶Êý£¬ ²»ÊǿɽÓÊܵĽ⣬ Áíһ½âÊÇ cos5x = -1/2. x = 24¡ã
ÓÚÊÇ Ëĸö½ÇÊÇ
72¡ã, 96¡ã,144¡ã, 48¡ã
sin3x + sin(7x - ¦Ð) = sin2x
ºͲ»ý
-2sin2xcos5x = sin2x
´˷½³ÌÓжþ½⣺sin2x = 0, x ÊÇ ¦Ð/2µÄÕû±¶Êý£¬ ²»ÊǿɽÓÊܵĽ⣬ Áíһ½âÊÇ cos5x = -1/2. x = 24¡ã
ÓÚÊÇ Ëĸö½ÇÊÇ
72¡ã, 96¡ã,144¡ã, 48¡ã
���༭ʱ��: 2023-06-21 16:24:24


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