a/y=x,
b/y=1/tan (2)=(1-x^2)/(2x)
֮y^2=a*a+2ab.
b/y=1/tan (2)=(1-x^2)/(2x)
֮y^2=a*a+2ab.
所跟帖: ƽÕý : µÚÒ»Ìâ½â·¨¾«²Ê£»µÚ¶þÌâ 2023-06-06 19:22:30
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