\[x^2 - x + 1 = 4x ,\]
\[x^2 + x + 1 = 6x \]
ʽ
\[ x^4 + x^2 + 1 = 24x^2\]
\[ \frac{x^2}{x^4 +1} =\frac{1}{23}\]
\[x^2 + x + 1 = 6x \]
ʽ
\[ x^4 + x^2 + 1 = 24x^2\]
\[ \frac{x^2}{x^4 +1} =\frac{1}{23}\]
���༭ʱ��: 2022-06-06 04:03:31
所跟帖: ÈüÀ¥ : µÚ¶þÊÇÆ½ÐÐËıßÐΣ¿ 2022-06-05 23:54:58
µÚÒ»Ìâ2022-06-06 03:48:31 [点击:1219]
全部跟贴
[] ÃÊÔÓà Vieta's theorem ½âһϠ¼¦Í·Èâ [209 b] 2022-06-06 06:15:51 [: 1180] (1453411)
[] ƯÁÁ¡£ ÈüÀ¥ [0 b] 2022-06-06 04:09:14 [: 1184] (1453409)