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所跟帖: ¼¦Í·Èâ :  ÍÆÇÃÒ»ÏÂÁ½¸öÈý½ÇÐεÄÃæ»ý±È   2021-09-10 07:26:38  


作者: ½Æß   ¸øÒ»¸ö¼òµ¥Ò»µãµÄ¼ÆËã 2021-09-11 00:13:05  [点击:1730]


»¹Óü¦ÀϰåµļǺš£

¼ÙÉèÈý½ÇÐÎABC µÄÃæ»ýΪ1£¬ ͼÖÐÂÌɫÇøÓòµÄÃæ»ýΪ G£¬ »ÆɫÃæ»ýΪY£¬ À¶ɫÃæ»ýΪB£¬ ÔòÖмäСÈý½ÇÐεÄÃæ»ý¾ÍÊÇ

1 - G- Y - B¡£

ÔõÑùÇó³ö G£¬ Y£¬ B Äأ¿ »¹¼ǵü¸¸öÔÂǰƽ½ÌÊڳöµÄÌâĿÂ𣿠Ç뿴ÕâÀ ƽ½ÌÊڸø³öµĴð°¸Êǣº



Èç¹ûÓà Ar£¨A£¬B£¬C£©±íʾÈý½ÇÐÎABC µÄÃæ»ý£¬ Ôò
\(\frac{1}{Ar(A,B,C)}+ \frac{1}{Ar(A,F,C)} = \frac{1}{Ar(A,D,C)}+ \frac{1}{Ar(A,E,C)}\)

Òò´ˣ¬ \(1 + \frac{1}{G} = \frac{1}{Ar(A,C',C)}+ \frac{1}{Ar(A,A',C)} = \frac{1}{\gamma} +\frac{1}{1-\alpha} = \frac{1 -\alpha + \gamma}{\gamma(1-\alpha)}\)¡£ ¼´ \( G = \frac{\gamma(1-\alpha)}{1-\alpha+\alpha\gamma}\)¡£

ͬÀí£¬ \( Y = \frac{\alpha(1-\beta)}{1-\beta+\alpha\beta}\), \( B = \frac{\beta(1-\gamma)}{1-\gamma+\beta\gamma}\)¡£

×îºó£¬ ÖмäСÈý½ÇÐεÄÃæ»ý = \( 1 - \frac{\gamma(1-\alpha)}{1-\alpha+\alpha\gamma} - \frac{\alpha(1-\beta)}{1-\beta+\alpha\beta} - \frac{\beta(1-\gamma)}{1-\gamma+\beta\gamma} \)¡£
���༭ʱ��: 2021-09-11 00:39:26

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